Global 1940 & 1943 Expansions Game Reports

@Trout

True - a Dessert Army is a regular PG / TG and land combat 3 units.

@the-captain

Due to the fact that whilst most of your rules are historically accurate, their execution I have some problems with. To fix that, I wrote an article on changes to The Captain’s rules:

https://www.axisandallies.org/forums/topic/37504/let-s-make-the-axis-and-allies-global-1940-expansion-rules-even-more-accurate?_=1636385389023

Hi @blaze-the-action-junkie

This is an interesting way of getting more tech rolls as well

https://www.axisandallies.org/forums/topic/13543/research-facilities-and-infrastructure-simple-rule-additions

I would make a Cruisers 10 and Bombers 15. Battleships fine at 20. I think.

I have to disagree.  Imagine Japan building a micro in western China or the Novosibirsk area.  That would allow a quick overrun of the unprotected Soviet territoriies while the Russians are cornered in Moscow.  It tales a fast unit four turns to get from the Chinese coast (where factories can be built) to Moscow, while a micro could bring troops to the front immediately.

Even a micro in the Shan State or Yunnan could be detrimental to India simply because of the added range. Though a micro is not as economical as a minor, it gives Japan a privilege it rarely ever gets early on: building inland.

Axis gets full advantage in the early turns, this forces them to get more aggression there for no reason for them to use peace as a shield and if I am playing as the allies, I’d rather have them be aggressive at turn 1 than turn 4.

Hi Erocco,
these numbers are based on a formula found during Classic time by Dauvio Vann and his friends, then improved and adjusted to better fit the need of Second Edition units. Here is one link in House Rule:
http://www.axisandallies.org/forums/index.php?topic=40346.msg1684954#msg1684954

Below, you get the whole formula and a short explanation:

@Baron:

@Dauvio:

It came to my attention that one of my formulas are already out there that I discovered 30 years ago.
http://www.axisandallies.org/forums/index.php?action=profile;u=185969 has also discovered the formula P^2*N=S
And just for fun you can try these formulas also. S/P^2=N. √(S/N)=P
P=POINTS
N=NUMBER OF UNITS
S=STRENGTH OF ONE KIND OF UNITS IN A TERRITORY
This formula should replace the punch formula. It is much better then the punch formula.

Now the next formula is (P100)/(C^26)=S
P=POINTS
C=COST
S=STRENGTH OF THE UNIT BASED ON COST
With this formula you can also price units according to their strength. √((P100)/(S6))=C
This formula is for points. (S*(C^2*6))/100=P

For better results for some of these formulas, have all your units cost ten times then what they are. These are some of the VANN FORMULAS I came up 30 years ago.

If you have any questions about these formulas, please ask.

I found how you can get the main part of Vann formula or Baron-Larrymarx according to a specific unit as benchmark.

I took the Fighter A3 D4 C10 and I wanted to convert into Tank A3 D3 C6 as benchmark (Baron-Larrymarx formula).

Then I saw what I did.

Power (of attacking Fighter): A3 * C6 (cost of Tank)/C10 (cost of Fg) * 1 Hit Point C6 (cost of Tank)/C10 (cost of Fg) = 1.08
You can reduce this equation because (cost of Tank)(cost of Tank)/ (cost of Fg)*(cost of Fg) is same to
(cost of Tank) IPCs^2 / (cost of Fg) IPCs^2 and give a simple ratio.

C6^2*A3/C10^2 = 1.08
36 squared IPCs 3 Power * 1 Hit /100 squared IPCs = 1.08 PowerHit Point

This explained what is hidden in Baron-Larrymarx formula:
Offence or defence strength factor= 36*Power/Cost^2.

The whole Enigma formula is
Refence unit Cost^2Power of the actual unit1 HP/Cost of the actual unit^2

So, the Basic offence or defence strength factor result (1.08, in this case) is express in Power*Hit Point
1^2*Power (of a given unit)*1 hit/Cost (of this same given unit)^2

And this formula can be adapt according to any benchmark, for instance a 1 IPC unit:
131 hit/10^2 = 0.300

And this is a very small number. That’s why Vann formula:
Strength= (Power100)/(Cost^26)

add an arbitrary 1001/6= 16.667…
So, 16.667131 hit/10^2 = 0.5
And this would provide the Fighter strength attack factor based on an hypothetical benchmark unit of √16.667 = 4.0825 IPCs.
A 5 IPCs revised Tank in Vann formula gives a Strength : 16.66731 hit/5^2 = 2.00 powerhit

Can you elaborate on the ship calculations?

Destroyer strength: .30144/8^2  = 0.675
Cruiser    strength: .60144/12^2= 0.600
Battleship strength: .701442.618/20^2 = 0.660

These numbers means that Destroyer is the most optimized unit for combat to buy for each IPC invested, then it is battleship and finally Cruiser.
Said otherwise, Cruiser is sub-optimal for the cost.
3 DDs C8 A3 D3 (A9 D9, 3 hits) will be stronger than 2 Cruisers C12 A6 D6 (A12 D12, 2 hits) if you can use a Battlecalc to test D10-sided values.

From stronger to weaker for 120 IPCs basis:
15 DDs A3 D3 (A45 D45)
6 BBs A7 D7 (A42 D42)
10 CAs A6 D6 (A60 D60)

You could use the same general rules for AA50, but you would have to pick one of the AA 50 setups (1941 or 1942) then add up the total cost of starting units to get the starting cash for each country. For one thing, I think there are less starting pieces for all the nations because AA 50 has a smaller map than the 1940 games so there are less pieces. Another thing is I think the prices are a little different in AA50 than in the 1940 games, plus you won’t have Tac Bombers or Mechanized Infantry as those units didn’t come out until the 1940 games.
Also, I’m not sure how you would handle China, since in AA50 they don’t actually get IPCs but rather 1 infantry for every 2 Chinese territories still under Chinese control at the beginning of their turn.
Other than a few small changes though, I think you could still adapt this idea to AA50.