Anniversary Edition Trivia

@squirecam said in Anniversary Errata Optional Rule: Escorts and Interceptors:

@the_good_captain said in Anniversary Errata Optional Rule: Escorts and Interceptors:

@cernel I played three games against forum members that made a point to do this as Germany while I was the allies. After the final repetition and significant impact from the aforementioned, I had to insist on Escorts and Interceptors.

I consider it less significant than the USA bomber strategy but I’m confident enough to make it an axiom of my own axis strategy …and share it in a video, obviously.

The escort and interceptor rule is required for a fair game IMHO. Moreover, no bombing strategy succeeded in eliminating a country’s ability to build tanks and weapons during ww2, and certainly not without getting through fighter screens first.

This answered my question krieghund.

I haven’t seen any warping of my boards (yet).

For the records: my box arrived undamaged, although I still have to check the playing pieces.

Okay aa50 can take 2-10+ hours. Global can take 6 hours to a few days.

The longest aa50 game I had lasted 32 hours because Germany was on the brink of losing, had a miracle defense against UK USA attack… Hit improved artillery with 1 tech roll that has been going for a long time suddenly has enough to kill south europe, survives another UK all in blast. Meanwhile Japans 30 tanks 5 bombers dies to Russia 25 inf 2 USA fighter (5 aa gun hits)  the Game that refused to end.

So global just takes long where as aa50 if it takes long it is because the game ending battles failed.

For the once liking the OOB map. Here is my scan of the 2nd edition map:
https://www.axisandallies.org/forums/index.php?topic=41446.0

When I have the time (my focus is currently on some Global 1940 customizations) I want to update at least the Iwo Jima and Honolulu mistake.

But looking at geography ‘errors’ don’t get me started on the Dutch East Indies and the fake islands they came up with.  :-)

Where are you from?

@shifty:

What kind of “program” are you writing?  What equation/algorithm are you using?

It’s written in BlitzMax. The source below should (hopefully :)) not be too hard to understand - if you have questions, feel free to ask:

' Compares 2nd ed. A&A tech dev cost/rate with Anniv. ed. A&A ' 20 turns to test; record turn number that a total of 2 breakthroughs were achieved.  Test 1 & 2 rolls/turn. ' If two breakthroughs aren't achieved, "turn 0" is recorded (ignored for graphing & turn average) ' (When going for two breakthroughs, two aren't achieved in about 2% for both 2nd and Anniv.) Strict Local breakthroughs, totalCost, turn, totalTurns Local answer[21], prefix$, graph$ Local breakthroughLimit = 2 For Local rolls = 1 To 2 ' actual rolls for 2nd Ed, Researchers for Anniv. Print;Print; Print rolls + " Tech Roll(s)/Researcher(s) per Turn:" Print; Print "2nd Edition" totalCost = 0 totalTurns = 0 For Local c = 0 To 20 answer[c] = 0 Next For Local test = 1 To 100000 ' a hundred thousand tests for accuracy breakthroughs = 0 turn = 0 While breakthroughs < breakthroughLimit And turn <= 20 turn :+ 1 totalCost :+ rolls * 5 ' each roll costs 5 IPCs For Local c = 1 To rolls If Rand(6) = 6 Then breakthroughs :+ 1 Next Wend totalTurns :+ turn If turn > 20 Then answer[0] :+ 1 Else answer[turn] :+ 1 EndIf Next ' display results For Local c = 1 To 20 graph = "" ' divide results by 1000 so each asterisk represents one percent For Local cc = 1 To Int(answer[c]/1000.0 + .5) graph :+"*" Next If c < 10 Then prefix = " " Else prefix ="" ' extra space for single digits Print prefix + c + " " + graph Next Print "Avg turn = " + totalTurns / 100000.0 Print "Avg cost = " + totalCost / 100000.0 Print; Print "Anniversary Edition" totalCost = 0 totalTurns = 0 For Local c = 0 To 20 answer[c] = 0 Next Local researchers ' researchers accumulate from turn to turn For Local test = 1 To 100000 researchers = 0 breakthroughs = 0 turn = 0 While breakthroughs < breakthroughLimit And turn <= 20 turn :+ 1 totalCost :+ rolls * 5 ' each researcher costs 5 IPCs researchers :+ 1 * rolls ' accumulate 1 researcher per "roll" Local success For Local c = 1 To researchers If Rand(6) = 6 Then success = True ' only one regardless of # of sixes rolled Next If success Then researchers = 0 ' eliminate accumulated researchers when successful breakthroughs :+ 1 EndIf Wend totalTurns :+ turn If turn > 20 Then answer[0] :+ 1 Else answer[turn] :+ 1 EndIf Next ' display results For Local c = 1 To 20 graph = "" ' divide results by 1000 so each asterisk represents one percent For Local cc = 1 To Int(answer[c]/1000.0 + .5) graph :+"*" Next If c < 10 Then prefix = " " Else prefix ="" ' extra space for single digits Print prefix + c + " " + graph Next Print "Avg turn = " + totalTurns / 100000.0 Print "Avg cost = " + totalCost / 100000.0 Next

I release it into the public domain (modify it as desired/convert it to the language of your choice).  breakthroughLimit is initially set for 2, which generated the first set of graphs in this thread (I hand-rounded the accuracy to a single decimal place when copy/pasting results in the thread). Setting it to 1 (i.e. stopping after getting one breakthrough) produced the second set above. I also made another, slightly tweaked version to generate the “only buy Researchers on turn 1” version for wodan46.

yea his comments are crap. typical just typical.