The Return of Axis & Allies Anniversary Edition available for UK?

Axis and Allies Anniversary Edition

Players must agree on the following options before starting the game:

Which Scenario are we playing?
a) 1941
b) 1942

How many victory cities will we play to?
a) 13 cities
b) 15 cities (default)
c) 18 cities

Research and Development allowed?
a) Yes
b) No

National Objectives allowed?
a) Yes
b) No

Dardanelles closed to sea movement?*
a) Yes
b) No

Fighter Escorts and Interceptors allowed?*
a) Yes
b) No

*Found in the official corrections/FAQ located here: https://axisallies.com/wp-content/uploads/2014/01/axis-allies-rules-anniversary-corrections-faqs.pdf

@rookeries Welcome to the forum :slightly_smiling_face:

Moving the UK plane to SZ 5 to attack the German transports there indeed is a valid combat move. The battle will be resolved according to the “defenseless transports”-rules on page 19 of the rulebook, sometimes referred to as “autodestruction”.

Scramble is not part of the ruleset here (you might mix that up with the rules for Global 1940).
Also there is nothing in the rules saying that planes must be accompanied by attacking ships.
So never leave your transports unprotected :smile:

You read it, so there must be people out there that r interested

Also…
All units are expendable, if the expenditure accomplishes something. Most units will be expended, but the challenge is to have them go in a way that they gave their money’s worth. Another important aspect of the game, which should be apparrent to a veteran player, or one with intelligence, is shielding of units. Some units (the more expensive ones) need to be protected by the less expensive ones. Infantry need to take hits for tanks, Destroyers and Cruisers should take hits for carriers… etc. Being able to scrape your expensive and better units out of a fight is essential for continuing operations and saving money. Make your enemy bleed more than you do.

I too worry that my romantic life (better half etc) may well have to go at some point.

Isn’t it sad that it has to be one or the other.

@shifty:

What kind of “program” are you writing?  What equation/algorithm are you using?

It’s written in BlitzMax. The source below should (hopefully :)) not be too hard to understand - if you have questions, feel free to ask:

' Compares 2nd ed. A&A tech dev cost/rate with Anniv. ed. A&A ' 20 turns to test; record turn number that a total of 2 breakthroughs were achieved.  Test 1 & 2 rolls/turn. ' If two breakthroughs aren't achieved, "turn 0" is recorded (ignored for graphing & turn average) ' (When going for two breakthroughs, two aren't achieved in about 2% for both 2nd and Anniv.) Strict Local breakthroughs, totalCost, turn, totalTurns Local answer[21], prefix$, graph$ Local breakthroughLimit = 2 For Local rolls = 1 To 2 ' actual rolls for 2nd Ed, Researchers for Anniv. Print;Print; Print rolls + " Tech Roll(s)/Researcher(s) per Turn:" Print; Print "2nd Edition" totalCost = 0 totalTurns = 0 For Local c = 0 To 20 answer[c] = 0 Next For Local test = 1 To 100000 ' a hundred thousand tests for accuracy breakthroughs = 0 turn = 0 While breakthroughs < breakthroughLimit And turn <= 20 turn :+ 1 totalCost :+ rolls * 5 ' each roll costs 5 IPCs For Local c = 1 To rolls If Rand(6) = 6 Then breakthroughs :+ 1 Next Wend totalTurns :+ turn If turn > 20 Then answer[0] :+ 1 Else answer[turn] :+ 1 EndIf Next ' display results For Local c = 1 To 20 graph = "" ' divide results by 1000 so each asterisk represents one percent For Local cc = 1 To Int(answer[c]/1000.0 + .5) graph :+"*" Next If c < 10 Then prefix = " " Else prefix ="" ' extra space for single digits Print prefix + c + " " + graph Next Print "Avg turn = " + totalTurns / 100000.0 Print "Avg cost = " + totalCost / 100000.0 Print; Print "Anniversary Edition" totalCost = 0 totalTurns = 0 For Local c = 0 To 20 answer[c] = 0 Next Local researchers ' researchers accumulate from turn to turn For Local test = 1 To 100000 researchers = 0 breakthroughs = 0 turn = 0 While breakthroughs < breakthroughLimit And turn <= 20 turn :+ 1 totalCost :+ rolls * 5 ' each researcher costs 5 IPCs researchers :+ 1 * rolls ' accumulate 1 researcher per "roll" Local success For Local c = 1 To researchers If Rand(6) = 6 Then success = True ' only one regardless of # of sixes rolled Next If success Then researchers = 0 ' eliminate accumulated researchers when successful breakthroughs :+ 1 EndIf Wend totalTurns :+ turn If turn > 20 Then answer[0] :+ 1 Else answer[turn] :+ 1 EndIf Next ' display results For Local c = 1 To 20 graph = "" ' divide results by 1000 so each asterisk represents one percent For Local cc = 1 To Int(answer[c]/1000.0 + .5) graph :+"*" Next If c < 10 Then prefix = " " Else prefix ="" ' extra space for single digits Print prefix + c + " " + graph Next Print "Avg turn = " + totalTurns / 100000.0 Print "Avg cost = " + totalCost / 100000.0 Next

I release it into the public domain (modify it as desired/convert it to the language of your choice).  breakthroughLimit is initially set for 2, which generated the first set of graphs in this thread (I hand-rounded the accuracy to a single decimal place when copy/pasting results in the thread). Setting it to 1 (i.e. stopping after getting one breakthrough) produced the second set above. I also made another, slightly tweaked version to generate the “only buy Researchers on turn 1” version for wodan46.

no way was a maus worth that many tigers! it may have had an awesome gun and armour, but it was one heavy beast. and slow too! it was so heavy that it couldn’t travel over conventional bridges!