are you aware that 0.99999999 repeating is equal to 1 ? watch this
say that o.999999 repeating equals x
10x = 9.9999999999 repeating
subtract 1x from both sides and you get
9x = 9.000000000
divide both sides by 9 and you get
x = 1
weird huh?
@FleetCommander:
are you aware that 0.99999999 repeating is equal to 1 ? watch this
say that o.999999 repeating equals x
10x = 9.9999999999 repeating
subtract 1x from both sides and you get
9x = 9.000000000divide both sides by 9 and you get
x = 1
weird huh?
no,
if you subtract 1 from 9.9 repeating, you get 8.9 repeating.
Yeah that is neat. One of those counter intuitive math things that doesnt seem right but is. =p
It’s kind of like the thing where you can get 1=2. I forget how that went, but I’ll see if I can’t figure it out again.
@FleetCommander:
are you aware that 0.99999999 repeating is equal to 1 ?
Yes, they are equal. It’s like saying the limit of 1-x as x approaches 0 equals 1.
@Grigoriy:
It’s kind of like the thing where you can get 1=2.
Let x=y, then
xy=x^2
xy-y^2=x^2-y^2
y(x-y)=(x+y)(x-y)
y=x+y
y=y+y
y=2y
1=2
:lol:
Well…
1/9 in decimal is 0.1111…
Thus, 0.999… is 9*1/9 = 1
not too suprising :)
@Dirt:
Let x=y, then
…
y(x-y)=(x+y)(x-y)
y=x+y
…
The good old “divide by zero” trick :)
nice is alos when you use only the positive solution of a square root and forget about the negative one.
nice is alos when you use only the positive solution of a square root and forget about the negative one.
I didn’t forget, I just…decided not to include it. Yeah. :roll:
