2013 - AAG 40 League

[Amon-Sul]

@Gamerman01:

@Amon-Sul:

So if U have more than 13 games played

the max number of games per player is 3 games unless the score is 2-1?

No, if you have more than 12 (or 13 or more, in other words) games played, then you can play someone until one of you has 3 wins.

So it is possible to go 0-2 against such a player, and then win the next 3 and be 3-2.  After that, games are not officially counted by Jenn (but I will still count them, unofficially  :-D)

Thats what i sadi. So 3 games is the max , but if the score is 2-1 after 3 games then U can have it more. Like tenis match in grand slam hehe  :lol:

Ok, god i have it confirmed i thought until recently U can play 5 games ehhe

[gamerman01]

“Best of 5” means you play until someone gets 3 wins, because then they have won more than half of the 5 games.  Is that maybe where things got “lost in translation”?

“Best of 3” means you are done at 2-0, because someone won more than half of the 3 games already.

[Amon-Sul]

i did not know it was best of 5.

i read somewhere here that is 5 games. So that is what led me in the wrong direction.

Thanks for the information :)

[Jennifer]

Correct. Â

last post on page 17:

Here’s the revised ruling:

• If both opponents have more than 12 completed games with at least 6 other players, then they may engage in another game.  If this should make it so each player has the same number of wins against the other (2 and 2) then a 5th tie breaker game may be played.  
  Considering the limit is currently 2 games with any specific pair of opponents with a 3rd game possible in the case of a tie, then having 6 unique opponents should not be hard to accomplish, if you have 12 games.

So if both you AND your opponent have 12 completed games, and you have both played against at least 6 different people (so yourself + 5 other members) then you may play up to 5 games instead of up to 3 games.  I’ll count a maximum of 3 wins then, instead of a maximum of 2 wins and it will be from the first reported game completions. Â

[seth4god]

@Cmdr:

Correct. � 
So if both you AND your opponent have 12 completed games, and you have both played against at least 6 different people (so yourself + 5 other members) then you may play up to 5 games instead of up to 3 games. � I’ll count a maximum of 3 wins then, instead of a maximum of 2 wins and it will be from the first reported game completions. �

I can play myself and have it count for league standings? Can I create a 2nd avatar and use that to rack up the 2 losses.  :wink:

[Jennifer]

you are a player, so you play 5 other people in the league and have 12 games minimum.

[seth4god]

I think you’ve lost the thread Jenn. So NOW you’re saying we only need 12 games against at least 5 other players? What happened to 6 different opponents?

@seththenewb:

@Cmdr:

Correct. �
So if both you AND your opponent have 12 completed games, and you have both played against at least 6 different people (so yourself + 5 other members) then you may play up to 5 games instead of up to 3 games. � I’ll count a maximum of 3 wins then, instead of a maximum of 2 wins and it will be from the first reported game completions. �

I can play myself and have it count for league standings? Can I create a 2nd avatar and use that to rack up the 2 losses.  :wink:

I was just getting on the awkward wording when you said both players need to play against at least 6 different people and then included the parenthesis that says yourself. I know what you meant, but as written it sounds like you can play yourself and have it count in the league.

[gamerman01]

I’m confused

Fortunately, it’s rare for somebody to have actually played 13 games against less than 5 (6?) opponents
In fact, if it’s 5 OTHER players, then….

4 players X 3 games = 12
It’s impossible to NOT have played at least 5 OTHER players and play 13 games, so if it’s 5 OTHER players, then that requirement is completely unnecessary and superfluous…  :roll:

[seth4god]

So which is it Jenn?

I admit the first post about number of opponent played was in jest . . .  but now your response has me confused. How many opponents and how many games exactly do you need to have under your belt before a best of 5 series counts in the league?

[Jennifer]

12 completed games.  At least 6 different players need to be involved in those 12 games.

Yes, the 12 games need to be COMPLETED and reported as complete before you can go best 3 of 5 games with an individual player or individual players.

[gamerman01]

That doesn’t help.  In fact, that makes it more confusing.  I was sure you said MORE than 12 games before, and now you’re saying 12.  Also, when you say “at least 6 different players need to be involved” I now know that you MIGHT be counting the player himself.

So you have to play against at least 5 other opponents?
It is impossible to play more than 12 games against only 4 opponents at best of 3 (3X4=12), so if you need to play 12 (13?) games, then the requirement of at least 5 opponents is needless confusion.

PLEASE

CLARIFY

[Jennifer]

ya know what, I’ll just quote it from page 17 again:

@Cmdr:

Here’s the revised ruling:

• If both opponents have more than 12 completed games with at least 6 other players, then they may engage in another game.  If this should make it so each player has the same number of wins against the other (2 and 2) then a 5th tie breaker game may be played. 
  Considering the limit is currently 2 games with any specific pair of opponents with a 3rd game possible in the case of a tie, then having 6 unique opponents should not be hard to accomplish, if you have 12 games.

[seth4god]

Ok, but you do see how that’s different than what you said right?

more than 12 completed games does not equal 12 completed games. And 6 OTHER players does not equal 6 players.

So what you said back in March is what counts yes?

[seth4god]

@seththenewb:

Ok, but you do see how that’s different than what you said right?

more than 12 completed games does not equal 12 completed games. And 6 OTHER players does not equal 6 players.

So what you said back in March is what counts yes?

Err, May

[Amon-Sul]

Have we reached the final verdict  8-)

[Jennifer]

Yes.  The hazards of using multiple computers in multiple states and trying to answer questions on the fly. :P

The quote from page 17 takes precedence.

[arathorn]

@Cmdr:

Yes.  The hazards of using multiple computers in multiple states and trying to answer questions on the fly. :P

The quote from page 17 takes precedence.

So the summary:

A minimum of 13 games must have been COMPLETED.

There must be a minimum of 6 different opponents among those 13 games.

There, conclusion given ;)

[gamerman01]

Thanks for digging that up and clarifying, Jenn

So I guess I have it correct in my spreadsheet (note at the bottom) all along…

Move along… nothing to see, here…

[Jennifer]

Sometimes I wish I still had mod powers in the league forum, sometimes I see it as a blessing in disguise not to have them!

Sometimes you feel like a nut, sometimes you don’t.  Destroyer captains are nuts, Aircraft Carrier captains are not!

[gamerman01]

ATTENTION

Seththenewbie found a very significant problem with Triple A that I have added to my list as item D at the bottom (I deleted one I had previously, so it still only goes to D and not E)

WHEN YOU GET SECOND, THIRD, FOURTH, OR FIFTH breakthrough on the same chart, and Triple A rolls to see what new tech you get, Triple A does NOT re-roll if it rolls one you already have.  It just gives you the next one on the list.

FOR EXAMPLE:

You have Super subs, Shipyards, Jets, and Radar already, with the USA.
Hallelujah, you get another breakthrough.
You should have a 50/50 shot at getting LRA or Heavy bombers.
But you don’t with Triple A, because when it rolls for your tech, it will give you LRA if you roll a 1,2,3,4 or 5.  You will only get heavy bombers if it rolls a 6.
Even if you only have 1 tech, it messes with your odds.
You have Improved mechanized infantry, and you get another land and production breakthrough.
Your chances are:
Improved artillery - 2/6 (1/3)
Rockets - 1/6
Paratroopers - 1/6
Increased production - 1/6
Bonds - 1/6

It should be 1/5 chance for each one you don’t have.

Solution:
Once you have a tech and you want to roll for that chart again, you should roll tech on the forum (I recommend rolling all tech dice on the forum - not just the 2nd die that determines which one you get, because once you roll a 6, Triple A automatically rolls the breakthrough die)
Jennifer has also decreed this, on a separate, non-league thread.  (No doubt she was going to add it to this or the rules thread)

See attached.

Triple A problems.doc